(1-9a^(-16))/(1-3a^(-8))

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Solution for (1-9a^(-16))/(1-3a^(-8)) equation:


D( a )

a = 0

1-(3*a^-8) = 0

a = 0

a = 0

1-(3*a^-8) = 0

1-(3*a^-8) = 0

1-3*a^-8 = 0

-3*a^-8 = -1 // : -3

a^-8 = 1/3

-8 < 0

1/(a^8) = 1/3 // * a^8

1 = 1/3*a^8 // : 1/3

3 = a^8

a^8 = 3 // ^ 1/8

abs(a) = 3^(1/8)

a = 3^(1/8) or a = -3^(1/8)

a in (-oo:-3^(1/8)) U (-3^(1/8):0) U (0:3^(1/8)) U (3^(1/8):+oo)

(1-(9*a^-16))/(1-(3*a^-8)) = 0

(1-9*a^-16)/(1-3*a^-8) = 0

-9*a^-16 = -1 // : -9

a^-16 = 1/9

-16 < 0

1/(a^16) = 1/9 // * a^16

1 = 1/9*a^16 // : 1/9

9 = a^16

a^16 = 9 // ^ 1/16

abs(a) = 9^(1/16)

a = 9^(1/16) or a = -9^(1/16)

a in { 9^(1/16)}

a in { -9^(1/16)}

a belongs to the empty set

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